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sorry if my profile pisses your sissy liberal ass off, if its woke its broke! MAGA 2028
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tuna 1 月 24 日 下午 9:20 
MandaPanda29

Level 60

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I GOT HACKED IGNORE ALL MSGS
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tuna Just now
[h1] Header Header Header Header Header [/h1]
Header text
Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Di

Manda
jese 1 月 24 日 下午 9:20 
m :steamthumbsdown: :steamsalty:
tuna 1 月 24 日 下午 9:18 
[h1] Header Header Header Header Header [/h1]
Header text
Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide
Header text
Header textttttttttttttttttt
Header text
Bold texfffffft Bold text
Underlined text Underlined text
Italic text Italic text
Strikethrough text Strikethrough text
Spoiler text
Doesn't parse [b]tags[/b] Doesn't parse tags

Render a horizontal rule

http://test-steamproxy.haloskins.io/steamstore Website link
tuna 1 月 24 日 下午 9:16 
+rep Aasessoem teamate Gogfort

Tuna
© Tuna Corporation. All rights reserved. All trademarks are property of their respective owners in the US and other countries.
jese 1 月 24 日 下午 9:15 
Substitute
x
=
c
o
s
α
,
α

[
0
:
;
π
]
x=cosα,α∈[0:;π]
T
h
e
n

x
+
1

x
2

=
2
(
2
x
2

1
)

c
o
s
α
+
s
i
n
α

=
2
(
2
c
o
s
2
α

1
)
Then∣x+
1−x
2


∣=
2

(2x
2
−1)∣cosα+sinα∣=
2

(2cos
2
α−1)

N
2
c
o
s
(
α

π
4
)

=
N
2
c
o
s
(
2
α
)

α

[
0
;
π
4
]

[
3
π
4
;
π
]
∣N
2

cos(α−
4
π

)∣=N
2

cos(2α) α∈[0;
4
π

]∪[
4


;π]
1)
α

[
0
;
π
4
]
α∈[0;
4
π

]
c
o
s
(
α

π
4
)
=
c
o
s
(
2
α
)

cos(α−
4
π

)=cos(2α)…
2.
α

[
3
π
4
;
π
]
α∈[
4


;π]

c
o
s
(
α

π
4
)
=
c
o
s
(
2
α
)

−cos(α−
4
π

)=cos(2α)

Manda